if p(x) = 6x^4 + x^3 -27x^2-2x +30 and zeros are root 2 and -root 2 find other zeros
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hey user here is your answer.......
-----> Given- Two zeros = √2 & -√2
x=√2 & x=-2
(x-√2)(x+√2)=0
◆Using identity=(a+b)(a-b)=a^2-b^2
◆(x)^2-(√2)^2
◆x^2-2
◆Now divide this by given expression.
◆◆◆◆DIVIDE REFER IN THE ATTACHMENT◆◆◆
By middle term splitting
◆6x^2+x-15
◆6x^2+10x-9x-15
◆Take common
●2x(3x+5)-3(3x+5)
◆(2x-3)(3x+5)=0
◆2x-3=0
◆x=3/2
&
◆3x+5=0
◆x=-5/3
◆So two zeros are -5/3 & 3/2
Hope it helps you☺️
-----> Given- Two zeros = √2 & -√2
x=√2 & x=-2
(x-√2)(x+√2)=0
◆Using identity=(a+b)(a-b)=a^2-b^2
◆(x)^2-(√2)^2
◆x^2-2
◆Now divide this by given expression.
◆◆◆◆DIVIDE REFER IN THE ATTACHMENT◆◆◆
By middle term splitting
◆6x^2+x-15
◆6x^2+10x-9x-15
◆Take common
●2x(3x+5)-3(3x+5)
◆(2x-3)(3x+5)=0
◆2x-3=0
◆x=3/2
&
◆3x+5=0
◆x=-5/3
◆So two zeros are -5/3 & 3/2
Hope it helps you☺️
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Answered by
1
Hey dear!!!
Refer the attachment above⏫⏫⏫✌✌✌
The other zeroes are -5/3 and 3/2
All the zeroes of the given polynomial are √2, -√2 , -5/3 and 3/2
Hope this helps you!!
Thanks!!!
[ Be Brainly ] ✌✌✌☺
Refer the attachment above⏫⏫⏫✌✌✌
The other zeroes are -5/3 and 3/2
All the zeroes of the given polynomial are √2, -√2 , -5/3 and 3/2
Hope this helps you!!
Thanks!!!
[ Be Brainly ] ✌✌✌☺
Attachments:
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