Question

If p(x) = 7 + 3 + − 5, where , , are constants and p(-7)=7, then find p(7)​

Answer 1

Step-by-step explanation:

${\huge{\boxed{\mathcal{\orange{ANSWER}}}}}$−17

Consider the given function.

f(x)=ax7+bx3+cx−5

Since, f(−7)=7

So,

f(−7)=a(−7)7+b(−7)3+c(−7)−5=7

−77a−73b−7c−5=7

−(77a+73b+7c+5)=7

77a+73b+7c+5=−7

77a+73b+7c=−12              (1)

Put x=7

f(7)=a(7)7+b(7)3+c(7)−5

f(7)=77a+73b+7c−5

f(7)=−12−5             from equation (1)

f(7)=−17

Hence, this is the answer.

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Answer 2

Answer:

Q.1- k=1

Q.2- 3

Step-by-step explanation:

Q.1- k=1

Q.2- 3