Question

If p(x)=7x^2-4√2x+c is completely divisible by (x-√2), then value of
c=_​

Answer 1

Answer:

The answer is $-6$

Step-by-step explanation:

Factor theorem :A polynomial P(x) is completely divisible by (x-a) if P(a)=0

Here $P(x)=7x^2-4\sqrt 2x+c$ and divisor $=x-\sqrt 2$

            $\Rightarrow P(\sqrt 2)=0$

            $\Rightarrow 7(\sqrt 2)^2-4\sqrt 2(\sqrt 2)+c=0\\\Rightarrow 7(2)-4(2)+c=0\\\Rightarrow 14-8+c=0\\\Rightarrow 6+c=0\\\Rightarrow c=-6$