if p(x)=7x²+x-2 find the value of p(0) +p(1)
Answers
Answered by
0
Answer:
p(0)+p(1) = 3
Step-by-step explanation:
p(0)=7(0)^2+0-2. p(1)=7(1)^2+1-2
p(0)= -2. p(1) = 7-2
p(1)=5
p(0)+p(1) = -2+5
= 3
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Answered by
0
Answer:
p(0)=7.0²+0-2
0-2
-2
p(1)=7.1²+1-2
7-1
6
-2+6
4
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Step-by-step explanation:
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