Math, asked by vanshika081, 4 months ago

if p(x)=7x²+x-2 find the value of p(0) +p(1)​

Answers

Answered by kavipriyak707
0

Answer:

p(0)+p(1) = 3

Step-by-step explanation:

p(0)=7(0)^2+0-2. p(1)=7(1)^2+1-2

p(0)= -2. p(1) = 7-2

p(1)=5

p(0)+p(1) = -2+5

= 3

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Answered by bhavanaRS
0

Answer:

p(0)=7.0²+0-2

0-2

-2

p(1)=7.1²+1-2

7-1

6

-2+6

4

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Step-by-step explanation:

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