Question

If P(x) = 9x^3 – 3x^2 + x - 5 , evaluate P(0) + P(-1)
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Answer 1

Answer:

$p(x) = 9 {x}^{3} - 3 {x}^{2} + x - 5 \\ then \\ p(0) = 9 ({0}^{3} ) - 3( {0}^{2} ) + (0) - 5 \\ = - 5 \\ p( - 1) = 9( - 1) {}^{3} - 3( - 1) {}^{2} + ( - 1) - 5 \\ = - 9 - 3 - 1 - 5 \\ = - 18 \\ {.}^{.} . \: p(0) - p( - 1) \\ = - 5 - ( - 18) \\ = - 5 + 18 = 13$