Question

If p(x)=A(4x²+2x+30)+B(2x²+8x+12)+C(-2x²+4x-4)and Qx=10x²+32x+24,find the value for A,B and C such that P(x)=Q(x)

Answer 1

Answer:

A=-2, B=6, C=-3

Step-by-step explanation:

p(x)=A(4x²+2x+30)+B(2x²+8x+12)+C(-2x²+4x-4)

=4Ax²+2Ax+A30+2Bx²+8Bx+B12-2Cx²+4Cx-C4

=(4A+2B-2C)x²+(2A+8B+4C)x(30A+12B-4C)= Q(x)=10x²+32x+24

=> 4A+2B-2C=10

2A+8B+4C=32

30A+12B-4C=24

From these 3 Equations, we get A=-2, B=6, C=-3