if p[x]=ax^2+bx+c and a+b+c=0 then one zero is [a]-b/a [b]c/a [c]b/c [d]none of these
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Step-by-step explanation:
If X1 and X2 are the two roots of the equation, then one root, say X1 = 1, obviously satisfies the equation so long as a + b + c = 0. To find the second root, remember that X1 + X2 = -b/a and 1 + X2 = -b/a which implies X2 = - (b/a) - 1 = - (b + a)/a.
Since c = - (a + b), then X2 = c/a
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