Question

If p(x) =ax^2 +bx+c is a quadratic polynomial then what is the relation of c/a with zeroes of p(x)? a. 0 b. 1c.sum of zeroes d. product of zeroes ​

Answer 1

Answer:

D.) Product of zeroes

Step-by-step explanation:

As, product of zeroes = c/a.

Answer 2

Answer: The correct option is d: the product of the zeros

Step-by-step explanation:

• Polynomial equation has 2 roots given by the following equation:
• $x_1=\frac{-b+\sqrt{b^2-4ac}}{2a}\\x_2 = \frac{-b-\sqrt{b^2+4ac}}{2a}$
• Multiply x1 and x2 we get,

$x_1x_2 = \frac{-b+\sqrt{b^2-4ac}}{2a} \frac{-b-\sqrt{b^2-4ac}}{2a} \\x_1x_2= \frac{b^2-(b^2-4ac)}{4a^2}\\x_1x_2=\frac{4ac}{4a^2}\\x_1x_2=\frac{c}{a}$

Therefore option d is correct.