if p(x)=ax^2+bx+c then a+b+c =0 , than one zeroes
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Answer:
p(1)=0
Step-by-step explanation:
P(x)=ax^2+bx+c ---- (1)
a+b+c=0 /Given --- (2)
By eqn 1 and 2
put x =1
P(1)=a+b+c=0
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