Question

if p(x) = ax+b, then zero of p(x)
i . a
ii. b
iii . -a/b
iv . -b/a
​

Answer 1

Answer:

(II). b

Step-by-step explanation:

p(x)= ax+b

p(0)=a*0+b

=0+b

=b

Answer 2

Answer:

(iv) -b/a

Step-by-step explanation:

When substituting x = -b/a in p(x),

$p(x) = a \frac{ - b}{a} + b$

$= - b + b$

$= 0$

So it is the zero of the polynomial