If p (x) = ax? + bx + c and a + c = b, then what is the point of p (x)? (A) x + 1 (b) 2x-1 (c) x-1 (d) 2x + 1
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Answer:
P(x)=ax
2
+bx+c
Hence, for real roots,
b
2
−4ac≥0
Q(x)=−ax
2
+dx+c
Hence, for real roots,
d
2
+4ac≥0
Now,
ac
=0
Now if ac<0
Then,
b
2
−4ac>0
Hence, P(x).Q(x) has atleast 2 real roots .
If ac>0
Then
d
2
+4ac>0
Hence, P(x).Q(x) has atleast 2 real roots .
Step-by-step explanation:
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