Question

If,p,(x)=ax+bx+c is a quadratic polynomial then what is relation of c/a with zeroes of p(x)

Answer 1

Answer:

it is related by

sum of zeroes is equal to c/a

Answer 2

$\huge\bigstar\sf\red{Answer:}$

$\sf{p(x)=ax^{2}+bx+c}$

$\sf{Relation:}$

$\sf{\dfrac{c}{a}=Product \ of \ zeroes.}$

$\sf{Extra \ information}$

$\sf{x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}}$

$\sf{\dfrac{-b}{a}=Sum \ of \ zeroes. }$

$\sf{Form \ of \ quadratic \ polynomial}$

$\sf{x^{2}-(Sum \ of \ zeroes)x+(Product \ of \ zeroes)}$