Question

If p(x) = ax2 + bx + c and a + b + c = 0, then one zero is
a)-b/a
b)c/a
c)b/c
d)none of these
answer in steps... don't spam..... urgent please​

Answer 1

Step-by-step explanation:

$ax {}^{2} + bx + c = 0 \\ a + b = - c \\ ax {}^{2} + bx = - c \\ put \: value \: of \: - c \\ ax {}^{2} + bx = a + b \\ now \: compare \: both \: sides \: you \: see \: x = 1 \\ so \: \frac{c}{a}$