Question

if p(x)=ax²+bx+c then find alpha - beta;2nd question 1st part

Answer 1

$p(x) = a {x}^{2} + bx + c \\ \alpha + \beta = \frac{ - b}{a} \\ \alpha \beta = \frac{c}{a} \\ ( \alpha - \beta ) {}^{2} = ( \alpha + \beta ) {}^{2} - 4 \alpha \beta \\ ( \alpha - \beta ) {}^{2} = \frac{ {b}^{2} }{ {a}^{2} } - 4 \frac{c}{a} \\ \alpha - \beta = \sqrt{ \frac{ {b}^{2} }{ {a}^{2} } - \frac{4c}{a} }$

mark as brainliest if helped