Question

If p(x)=ax²+bx+c, then” is equal to:​

Answer 1

Answer:

Option d is the correct answer as alpha + beta = -(b)/a is an identity where b is the coefficient of x and a is the coefficient of x². This discussion on If p(x) = ax2 + bx + c, then - b/a is equal toa)0b)1c)product of zeroesd)sum of zeroesCorrect answer is option 'D'.

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

COMPLETE QUESTION

$\displaystyle \sf{ If \: \: p(x) = a {x}^{2} + bx + c \: \: then \: - \frac{b}{a} = }$

a) 0

b) 1

c) Product of zeroes

d) Sum of zeroes

EVALUATION

Here the given polynomial is

$\displaystyle \sf{p(x) = a {x}^{2} + bx + c }$

Now we have

$\displaystyle \sf{ Sum \: of \: the \: zeroes = - \frac{b}{a} }$

$\displaystyle \sf{ Product \: of \: the zeroes =\frac{c}{a} }$

For example , Consider the Quadratic polynomial

$2 {x}^{2} - 10x + 12$

Comparing with

$a {x}^{2} + bx + c$

We get

$a = 2 \: , \: b = - 10 \: , \: c = 12$

So

$\sf{Sum \: of \: the \: Zeroes \: } = \displaystyle \: - \frac{b}{a} = - ( - \frac{10}{2} ) = 5$

$\sf{Product \: of \: the \: Zeroes \: } = \displaystyle \: \frac{c}{a} = \frac{12}{2} = 6$

FINAL ANSWER

Hence the correct option is

d) Sum of zeroes

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