Question

if p(x)= ax⁷+bx⁵+cx³+3 and p(7)=2, p(-7)=?​

Answer 1

Answer:

P(-7) = 4

Step-by-step explanation:

P(x) = ax7+bx5+cx3+3

P(7) = a(7)7+b(7)5+c(7)3+3 (equation 1)

P(-7) = a(−7)7+b(−7)5+c(−7)3+3

P(-7) = −a(7)7−b(7)5−c(7)3+3 (equation 2)

Add equation 1 and equation 2

P(7) +P(-7) = 3 + 3

P(7) +P(-7) = 6

P(-7) = 6 - P(7)

P(-7) = 6 - 2

P(-7) = 4

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Answer 2

Answer:

Heres the solution

Step-by-step explanation: