if p(x) divisible by (x-3)then find the remainder of p(x)=2x4 +2x4+3x3- 26x2- 5x+6
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Answer:
x-3= 0
x = 3
p(3) = 2(3)4+2(3)4+3(3)3-26(3)2-5(3)+6
= 2(81)+2(81)+3(27)-26(9)-15+6
= 162+162+81-234-9
342+81-243
423-243
180
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