Question

If p(x) = g(x) q(x) + r(x), degree of p(x) = 6, degree
of g(x) = 3, and degree of r(x) = 0, then degree of
q(x) is​

Answer 1

Answer:

Hence the degree of p(x) is 7

Step-by-step explanation:

The degree of p(x) is always equal to the sum of the degrees of q(x) and g(x) because we multiply q(x) and g(x). Therefore in this question the degree shall be 4+3=7; Hence the degree of p(x) is 7

Hope this is helpful

Answer 2

Answer:

Step-by-step explanation:

(i) deg p(x)=deg q(x) (ii) deg q(x)=deg r(x) (iii) deg r(x)=0. Medium ... So here the degree of quotient will be equal to degree of dividend when the divisor is constant. ... Here, p(x) = x3+x, g(x) = x2, q(x) = x and r(x) = x. Degree of q(x) and r(x) ... Verify divison algorithm for the polynomial f(x)=8+20x+x2−6x3 by g(x)=2+5x−3x2.