Question

if p x is equal to x square - 4 x + 3 evaluate P2 -p- 1 + p1 /2

Answer 1

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Answer 2

$p(2)-p(-1)+p(\frac{1}{2})=\frac{-31}{4}$

Step-by-step explanation:

Given : $p(x)=x^2-4x+3$

To find : Evaluate $p(2)-p(-1)+p(\frac{1}{2})$

Solution :

First we find the individual terms,

$p(x)=x^2-4x+3$

Put x=2,

$p(2)=2^2-4(2)+3$

$p(2)=4-8+3$

$p(2)=-1$

Put x=-1,

$p(-1)=(-1)^2-4(-1)+3$

$p(-1)=1+4+3$

$p(-1)=8$

Put $x=\frac{1}{2}$,

$p(\frac{1}{2})=(\frac{1}{2})^2-4(\frac{1}{2})+3$

$p(\frac{1}{2})=\frac{1}{4}-2+3$

$p(\frac{1}{2})=\frac{5}{4}$

Substitute all values in the expression,

$p(2)-p(-1)+p(\frac{1}{2})=-1-8+\frac{5}{4}$

$p(2)-p(-1)+p(\frac{1}{2})=\frac{-9\times 4+5}{4}$

$p(2)-p(-1)+p(\frac{1}{2})=\frac{-31}{4}$

#Learn more

P (x is equal to X 4 - 3 x square + 4 x + 5) x is equal to x square minus x + 1 ​

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