Question

if p x is equal to x square minus 2 root 2 X + 1 then find the value of p 2 root 2​

Answer 1

Answer:

1

Explanation:

p(x)= $x^{2} -2\sqrt{2} x+1$

$p(2\sqrt{2})=2\sqrt{2} ^{2} -2\sqrt{2} (2\sqrt{2} )+1\\p(2\sqrt{2})=2\sqrt{2} ^{2} -2\sqrt{2} ^{2}+1\\p(2\sqrt{2})= 1$