Question

if p (x) is equals to x cube -1 then find P (1)​

Answer 1

Answer:-

$\sf p(x) = {x}^{3} - 1$

So,

$\sf p(1) = {1}^{3} - 1 = 1 - 1 = 0$

So,

$\sf p(1) = 0$

Answer 2

p(x)=x³-1

p(1)=1³-1

=1-1

=0

This is your answer.