Math, asked by hishanth, 9 months ago

if p(x)=x^15-2004-x^14-2004x^13..........2004x^2-2004-x. then find the calue of p(2003)​

Answers

Answered by as5123106
2

Step-by-step explanation:

Remainder Theorem we will use over here that will tell us that the value of P(2003),

2003 | 1 -2004 +2004 -2004 +2004 -2004 +2004 ...

         |    2003 -2003  2003 -2003  2003 -2003 ...

      ---------------------------------------------

            1    -1     1    -1     1    -1     1 ...

The remainder is 1 after division we perform with odd power & -1 after with  even power.  

last term is 1 so P(2003)=1

HOPE IT HELPS YOU

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Answered by 1KingArjun
0

Step-by-step explanation:

Here we will use the REMAINDER THEOREM to find the value of P(2003),

2003 | 1 -2004 +2004 -2004 +2004 -2004 +2004 ...

|    2003 -2003  2003 -2003  2003 -2003 ...

---------------------------------------------

1    -1     1    -1     1    -1     1 ...

The remainder is 1 after division.

We perform with odd power & -1 after with even power.  

∴ The last term is 1 so P(2003) = 1

Hope it Helps !!

Plzzzz Mark As Brainliest!!!!

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