Question

if p(X)=x^2-1 find the p(1) ;p(2)


please fast please​

Answer 1

P(x) = x^2 - 1

(i) p(1) = 1^2 - 1

= 1 - 1

= 0

(ii) p(2) = 2^2 - 1

= 4 - 1

= 3

Answer 2

Given:-

p(x) = x² - 1

Thus,

p(1) = (1)² - 1

= 1 - 1

= 0

Or,

p(2) = (2)² - 1

= 4 - 1

= 3