Question

if p(x)=x-_2 2√2x+1 ,then p(2√2) is equal to A.-6 B.6C.2 D.-2​

Answer 1

Answer:

may be my answer helps you

p(x) = x 2 -2√2x+1

p(2√2) = + 2√22 - 2√2 × 2√2 + 1

p(2√2) = 8 - 8 + 1

p(2√2) = 1

Hence, option B

Answer 2

Step-by-step explanation:

Solution:

Let p(x) = x^2 - 2√2x + 1,

Therefore, p(2√2) = (2√2)^2 - 2√2(2√2) + 1

= 8 - 8 + 1

= 1