Question

IF p(x) = x^2 - 2root 2x + 1 then find p (2root2)

Answer 1

Answer:

Step-by-step explanation:

parthtoshatwad

Secondary SchoolMath 5+3 pts

If p(x)=x² - 2√2x + 1, then find value of p(2√2).

Report by Sherrya 02.10.2015

Answers

lifeislife

Lifeislife Ace

p(x)=x²-2√2x+1.

p(2√2)=(2√2)²-(2√2*2√2)+1

p(2√2)=(2√2)²- (2√2)²+1

=0+1.

=1.

Therefore, the answer is 1.

Thank you.

Hope this will help you.

Answer 2

Answer:

$p(x) = (2 \sqrt{2}) \\ p(x) = {x}^{2} - 2 \sqrt{2} + 1 \\ p(2 \sqrt{2}) \: = (2 \sqrt{2})^{2} - (2 \sqrt{2})(2 \sqrt{2} ) + 1 \\ = 4( \sqrt{2} )^{2} - 4( \sqrt{2} )^{2} + 1 \\ = (8 - 8) + 1 \\ = 1 \\therefore \: \: \: \: \: \: \: .\: \: p(2 \sqrt{2}) = 1$

Step-by-step explanation:

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