Question

If p(x)=x^2+2x+1 then find the value of p(0),p(1)


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Answer 1

Answer:

1, 4

Step-by-step explanation:

p(x) = x^2+2x+1

put x= 0 in p(x)

p(0)= (0) ^2 +2(0) +1

= 0+0+1

=1

Now,

put x = 1 in p(x)

p(1)= (1)^2+2(1)+1

=1+2+1

=4

Answer 2

Answer:

ans is 1,4

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