Math, asked by gavlidevansh, 6 days ago

If P(x) =

x^2-√2x + 1, then find the value of P(2√2).

Answers

Answered by chemistrywala
1

Step-by-step explanation:

P(x) = -2x+1

P(22) = (22)² - 2(22) + 1

= 8-4+1 = 5

Answered by janaprateem1409
0

Answer:

5

Step-by-step explanation:

P(2\sqrt{2})  = (2\sqrt{2})^2 -  \sqrt{2}(2\sqrt{2}) + 1

P(2\sqrt{2})  = 8 - 4 + 1

P(2\sqrt{2})  = 5

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