Question

If p(x)=x^2+3x-4 find p(2) + p(0)

Answer 1

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☆ ANSWER:-

▪︎ Given:-

$\tt\leadsto \: p(x) = {x}^{2} + 3x - 4$

▪︎ To Find:-

• The value of p(2) + p(0).

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▪︎ So,

• Lets put 2 and 0 in the value of x and add them.

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1.

$\tt\mapsto \: p(2) = (2)^{2} + 3(2) - 4 \\ \\ \tt\mapsto \: p(2) = 4 + 6 - 4 \\ \\ \tt\mapsto \: p(2) = 10 - 4 \\ \\ \tt\mapsto \: p(2) = 6...(1)$

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2.

$\tt\mapsto \: p(0) = ({0})^{2} + 3(0) - 4 \\ \\ \tt\mapsto \: p(0) = 0 + 0 - 4 \\ \\ \tt\mapsto \: p(0) = -4...(2)$

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▪︎ Therefore,

$\sf \mapsto \: p(2) + p(0) = 6 + ( - 4) \\ \\ \sf \mapsto \: p(2) + p(0) = 6 - 4 \\ \\ \sf \mapsto \: p(2) + p(0) = 2.$

▪︎ Therefore the value of p(2) + p(0) = 2.

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