Question

if P (x) =x^2 -3x +5 , find P(0)+P(1)

Answer 1

Answer:

8

Step-by-step explanation:

If p(x) =x^2 -3x+5

So, p(0) = x^2 -3x+5

=0^2 -3*0 +5

=0-0+5

=5

Just put the value of p be 0 in the given equation.

Now put the value of p be 1 .

So, p(1) = x^2-3x+5

=1^2-3*1+5

=1-3+5

=3

So p(0) = 5

&

p(1) = 3

So ,

=p(0) + p(1)

=5 +3

= 8 .

hope it helps you .

Answer 2

Given,

$: \implies p(x) = {x}^{2} - 3x + 5$

To Find,

$: \implies p(0) + p(1)$

Solution,

First Find p(0)

$: \implies p(x) = {x}^{2} - 3x + 5 \\ \\ : \implies p(0) = {(0)}^{2} - 3(0)+ 5 \\ \\ : \implies p(0) = 0 - 0 + 5 \\ \\ : \implies p(0) = 5 \: \: \: •••(1)$

Then Find p(1)

$: \implies p(x) = {x}^{2} - 3x + 5 \\ \\ : \implies p(1) = {(1)}^{2} - 3(1)+ 5 \\ \\ : \implies p(1) = 1 - 3 + 5 \\ \\ : \implies p(1) = 3 \: \: \: •••(2)$

Required Answer,

$: \implies p(0) + p(1) \\ \\ : \implies5 + 3 \\ \\ : \implies 8$