if p(x)=x^2+4,find the value of p(1)
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satindersingh2:
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here..
p(x)=x²+4
so p(1)=?
here p(x)=p(1)
I. e. x=1
p(1)=1²+4
p(1)=1+4
p(1)=5
hope this helps you Plzzz mark it as brainaliest answer
p(x)=x²+4
so p(1)=?
here p(x)=p(1)
I. e. x=1
p(1)=1²+4
p(1)=1+4
p(1)=5
hope this helps you Plzzz mark it as brainaliest answer
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