Question

If p(x) = x^2 – 4x + 3, evaluate p(2) – p(- 1)

Answer 1

Answer:

$p(x) = {x}^{2} - 4x + 3 \\ \\ so \: \: \: p(2) = {2}^{2} - 4 \times 2 + 3 \\ \\ = 4 - 8 + 3 \\ \\ p(2) = - 1 \\ \\ \\ so \: \: \: p( - 1) = { - 1}^{2} - (4 \times - 1) + 3 \\ \\ = 1 - ( - 4) + 3 \\ \\ = 1 + 4 + 3 \\ \\ p( - 1) = 8 \\ \\ \\ so \: \: \: p(2) - p( - 1) = - 1 - 8 \\ \\ = - 9$

HOPE THIS HELPS YOU

Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

We have p(x) = x² - 4x + 3

p(2) - p(-1) + p(1/2)

= (2² - 4 × 2 + 3) - {(-1)² - 4(-1) + 3} + {(½)² - 4 × ½ + 3}

= (4 - 8 + 3) - (1 + 4 + 3) + (¼ - 2 + 3)

= - 1 - 8 + ⁵/₄

= - 9 + ⁵/₄

= (-36 + 5)/4

= -31/4 Ans.