If p (x) = x^2-4x+3 , evaluate p (2)-p (1)+p (0)
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p(2)=2^2-4(2)+3
=4-8+3
=-1
p(1)=1-4+3
=0
p(0)=3
p(2)+p(1)+p(0)=-1+0+3
=2
=4-8+3
=-1
p(1)=1-4+3
=0
p(0)=3
p(2)+p(1)+p(0)=-1+0+3
=2
KhushiGangwal:
thnx
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