Question

If p(x)=x^2-4x+3,evaluate: p(2)-p(-1)+p(1/2)

Answer 1

Answer:

${x}^{2} - 4x + 3 = 0$

$p(2) = {2}^{2} - 4(2) + 3$

$p(2) = 4 - 8 + 3$

$p(2) = (- 1)$.............1

$p( - 1) = { - 1}^{2} - 4( - 1) + 3$

$p( - 1) = 1 + 4 + 3$

$p( - 1) = 8$...............2

$p( \frac{1}{2} ) = {\frac{1}{2} }^{2} - 4 (\frac{1}{2} ) + 3$

$p( \frac{1}{2} ) = \frac{1}{4} - 2 + 3$

$p( \frac{1}{2}) = \frac{1}{4} + 1$

$p ( \frac{1}{2} ) = \frac{1 +4}{4}$

$p( \frac{1}{2}) = \frac{ 5}{4}$..............3

Now, according to the question

$p(2) - p( - 1) + p( \frac{1}{2} )$

From eq. 1,2,3

$( - 1) - (8) + ( \frac{5}{4} )$

$-9+ \frac{ 5}{4}$

$\frac{ -31}{4}$

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Answer 2

Answer:

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Step-by-step explanation:

(4-8+3)-(1+4+3)-(1/4-2+3)

-1-8-5/4

(-4-32-5)/4

-41/4