If p (x) = x^2-4x+3 evaluate p (2) + p (-1) - p (1/2)
Answers
Answered by
889
p(x)=x²-4x+3
so,
p(2)= 2²-4×2+3= 4-8+3= (-1)
p(-1)= (-1)²-4(-1)+3= 1+4+3= 8
p(1/2)= (1/2)²-4(1/2)+3= (1/4)-2+3 =1/4+1 =5/4
now,
p(2)+p(-1)-p(1/2)
=(-1)+8-5/4
=7-5/4
=28-5/4
=23/4
so,
p(2)= 2²-4×2+3= 4-8+3= (-1)
p(-1)= (-1)²-4(-1)+3= 1+4+3= 8
p(1/2)= (1/2)²-4(1/2)+3= (1/4)-2+3 =1/4+1 =5/4
now,
p(2)+p(-1)-p(1/2)
=(-1)+8-5/4
=7-5/4
=28-5/4
=23/4
ReetChauhan1112:
mrk as brniest
The answer is wrong its -1+8-5/4
sorry
but now i corrected it
I know...i have done mistake in addition...sorry
No its ok I was just correcting u
i am right....
yes
u r right
:-)
Answered by
237
Answer:
hey mate....
I hope it may be helpful for you.....by
Step-by-step explanation:
P(x)=x²-4x+3
so,
p(2)= 2²-4×2+3= 4-8+3= (-1)
p(-1)= (-1)²-4(-1)+3= 1+4+3= 8
p(1/2)= (1/2)²-4(1/2)+3= (1/4)-2+3 =1/4+1 =5/4
now,
p(2)+p(-1)-p(1/2)
= -1+8-5/4
=7-5/4
=28-5/4
=23/4
Answer is 23/4 or 5.75.
I hope it may be helpful for you.
I hope it may be helpful for you.Thank you!
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