If, p(x) = x^2 – 4x +3,
evaluate p^2 – p^-1 + p^1/2
Answers
Answered by
1
Answer:
Step-by-step explanation:
p(x)=x²-4x+3
so,
p(2)= 2²-4×2+3= 4-8+3= (-1)
p(-1)= (-1)²-4(-1)+3= 1+4+3= 8
p(1/2)= (1/2)²-4(1/2)+3= (1/4)-2+3 =1/4+1 =5/4
now,
p(2)+p(-1)-p(1/2)
=(-1)+8-5/4
=7-5/4
=28-5/4
=23/4
Answered by
1
Step-by-step explanation:
We have p(x) = x² - 4x + 3
p(2) - p(-1) + p(1/2)
= (2² - 4 × 2 + 3) - {(-1)² - 4(-1) + 3} + {(½)² - 4 × ½ + 3}
= (4 - 8 + 3) - (1 + 4 + 3) + (¼ - 2 + 3)
= - 1 - 8 + ⁵/₄
= - 9 + ⁵/₄
= (-36 + 5)/4
= -31/4 Ans.
Similar questions
World Languages,
4 months ago
Science,
4 months ago
English,
4 months ago
Math,
9 months ago
Biology,
9 months ago
Computer Science,
1 year ago