If p(X)=X^2-5X+6,find p(2),p(1),p(3) and p(-2)
Answers
Answered by
0
Answer:
helo guys its your answer
Step-by-step explanation:
P(x)=x2-5x-6 find the value of p(1),p(2),p(3),p(0),p(-1),p(-2),p(-3). step (2)p(3), p(0), p(–1), p(–2), p(– 3). ... v ) p(-2) = (-2)² - 5(-2) - 6 = 4 + 10 - 6 = 8
Answered by
0
Answer:
Hey champion, here is your answer..
p(2)= 0
p(2)= 0p(1)= 2
p(2)= 0p(1)= 2p(3)= 0
p(2)= 0p(1)= 2p(3)= 0p(-2)= 20
Step-by-step explanation:
P(2)= 2^2- 5×2+ 6
4-10+6
-6+6
0 Ans..
P(1)= 1^2-5×1+6
1-5+6
-4+6
+2 Ans..
P(3)= 3^2-5×3+6
9-15+6
-6+6
0 Ans..
P(-2)= (-2)^2 - 5(-2) + 6
4+ 10+6
20 Ans..
Similar questions
Math,
3 months ago
Math,
3 months ago
Math,
3 months ago
Social Sciences,
6 months ago
English,
10 months ago
Social Sciences,
10 months ago