Question

If p(X)=X^2-5X+6,find p(2),p(1),p(3) and p(-2)​

Answer 1

Answer:

helo guys its your answer

Step-by-step explanation:

P(x)=x2-5x-6 find the value of p(1),p(2),p(3),p(0),p(-1),p(-2),p(-3). step (2)p(3), p(0), p(–1), p(–2), p(– 3). ... v ) p(-2) = (-2)² - 5(-2) - 6 = 4 + 10 - 6 = 8

Answer 2

Answer:

Hey champion, here is your answer..

p(2)= 0

p(2)= 0p(1)= 2

p(2)= 0p(1)= 2p(3)= 0

p(2)= 0p(1)= 2p(3)= 0p(-2)= 20

Step-by-step explanation:

P(2)= 2^2- 5×2+ 6

4-10+6

-6+6

0 Ans..

P(1)= 1^2-5×1+6

1-5+6

-4+6

+2 Ans..

P(3)= 3^2-5×3+6

9-15+6

-6+6

0 Ans..

P(-2)= (-2)^2 - 5(-2) + 6

4+ 10+6

20 Ans..