Question

if p(x)=x^2-5x-6,then find the number of zeroes of p(x)
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Answer 1

Answer:

${x}^{2} - 5x - 6 \\ = > {x}^{2} - 3x - 2x - 6 \\ = > x(x - 3) - 2(x - 3) \\ (x - 2)( x - 3) \\ = > x = 2 \: \: \: \: or \: \: \: \: \: x = 3$