Question

if p(x)=x^2-root2x+1,then find the value of p(2root2)

Answer 1

Answer:

5

Step-by-step explanation:

just plugging in the value for x = $2\sqrt{2}$

we get,

p($2\sqrt{2}$ ) = $(2\sqrt{2} )^{2} - \sqrt{2} (2\sqrt{2}) +1$

p($2\sqrt{2}$ ) = 8 - 4 + 1

p($2\sqrt{2}$ ) = 5