Question

If P(x)=x+2 then find P(1) and P(2)​

Answer 1

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Answer 2

Answer:

Let p(x)=x+2

Let p(x)=x+2Replace x by 1

Let p(x)=x+2Replace x by 1p(1)=1+2=3

Let p(x)=x+2Replace x by 1p(1)=1+2=3Replace x by 2

Let p(x)=x+2Replace x by 1p(1)=1+2=3Replace x by 2p(2)=2+2=4

Let p(x)=x+2Replace x by 1p(1)=1+2=3Replace x by 2p(2)=2+2=4Replace x by −1

Let p(x)=x+2Replace x by 1p(1)=1+2=3Replace x by 2p(2)=2+2=4Replace x by −1p(−1)=−1+2=1

Let p(x)=x+2Replace x by 1p(1)=1+2=3Replace x by 2p(2)=2+2=4Replace x by −1p(−1)=−1+2=1Replace x by −2

Let p(x)=x+2Replace x by 1p(1)=1+2=3Replace x by 2p(2)=2+2=4Replace x by −1p(−1)=−1+2=1Replace x by −2p(−2)=−2+2=0

Let p(x)=x+2Replace x by 1p(1)=1+2=3Replace x by 2p(2)=2+2=4Replace x by −1p(−1)=−1+2=1Replace x by −2p(−2)=−2+2=0Therefore, 1,2,−1 are not the zeroes of the polynomial x+2. Only −2 is zero of the polynomial.

Step-by-step explanation:

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