Question

 If P(x) = x^2 - x -2 as one of its roots, find the other root.​

Answer 1

Answer:

x^2 - x - 2

x^2 -2x + x - 2

x(x-2)+1(x-2)

(x+1)(x-2)

x+1=0

x = -1

x-2 = 0

x = 2

roots are -1 and 2

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Answer 2

Answer:

P(x)= x²-x-2 = 0

= x²-2x+x-2 = 0

= x(x-2)+ 1(x-2) = 0

= (x-2) (x+1) = 0

consider (x-2) = 0

= x = 2

consider (x+1) = 0

= x = -1

so 2 and -1 are the zeroes of P(x)