Question

if p(x)=x^2-x+k,p(1)=-1 then find k​

Answer 1

Answer:

k=0

Step-by-step explanation:

• p(x) = x^2-x+k
• p(1) = (1)^2-1+k
• =1-1+k=0
• therefore, k =0.

Answer 2

Answer:

k = -2.

Step-by-step explanation:

here the given equation is :

$p(x) = x^{2} - x + k$

and the value of p(x) given as :

$p(x) = - 1$

so the value of x will be equal to -1.

now , substituting the value of p(x) in given equation =

$p( - 1) = ( - 1)^{2} - ( - 1) + k = 0 \\ p( - 1) = 1 + 1 + k = 0 \\ p( - 1) = 2 + k = 0 \\ p( - 1) = k = - 2$

therefore the value of k is equal to -2.