if p(x) = x^3 - 1 then find the value p(1) +p(-1) ap
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Answered by
1
if p(x)=x^3-1,
then you have to substitute 1 and -1 in x.
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Answered by
1
Answer:
-2
Step-by-step explanation:
Solution :
Given that p(x) =x^3 - 1. - - - - (i)
We have to find p(1)+p(-1)=?
Putting x=1 in equation (i)
P(1)=1^3-1=1-1=0 - - - - (ii)
Again, putting x=-1 in equation(i)
P(-1)=(-1)^3 - 1=-1-1=-2 - - - - (iii)
Now adding equation (ii) & (iii), we get
P(1)+p(-1)=0-2
=-2 ans.
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