Question

If p(x)=x^3-1,then the value of p(1)+p(-1) is

Answer 1

Answer: -2

Step-by-step explanation:

P(1)= x^3-1

P (1)= 1^3-1

=1 - 1

= 0

P (-1)= -1^3-1

= -1-1

= -2

P (1)+P (-1) = 0-2

= -2

Answer is (-2)

Answer 2

Given,

p(x) = x³-1

To find,

p(1)+p(-1)

Solution,

The value of p(1) can be calculated by substituting the value of x as 1 in the equation p(x) = x³-1.

⇒    So , p(1) = (1)³-1 = 0

p (1) = 0

Similarly, The value of p(-1) can be calculated by substituting the value of x as -1 in the equation p(x) = x³-1.

⇒    So, p(1) = (-1)³-1 = 0

p (1) = -2.

⇒   Therefore, p(1) + p(-1) = 0 + (-2)

Hence, the value of p(1) + p(-1) = -2