Question

If p(x) = x^3-1, then the value of P(1)+P(-1) is

Answer 1

Things to know

• Definition of symbols
• Functions

If we have $P(x)=x^3-1$ we can substitute the value of $x$ to get the function value.

Solution

$P(1)$ is the value of $P(x)$ at $x=1$. $P(-1)$ is the value of $P(x)$ at $x=-1$.

So,

$P(1)+P(-1)$

$=(1)^3-1+(-1)^3-1$

$=1-1-1-1$

$=-2$

The value of $P(1)+P(-1)$ is $-2$.

Answer 2

Answer:

Things to know

Definition of symbols

Functions

If we have P(x)=x^3-1P(x)=x

3

−1 we can substitute the value of xx to get the function value.

Solution

P(1)P(1) is the value of P(x)P(x) at x=1x=1 . P(-1)P(−1) is the value of P(x)P(x) at x=-1x=−1 .

So,

P(1)+P(-1)P(1)+P(−1)

=(1)^3-1+(-1)^3-1=(1)

3

−1+(−1)

3

−1

=1-1-1-1=1−1−1−1

=-2=−2

The value of P(1)+P(-1)P(1)+P(−1) is -2−2 .

hope it help u