If P(x)=x^3 - 1 then the value of P(1) + P(-1) is
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Answer:
p(x) = x³ - 1
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now,
p(1) = (1)³ - 1 = 1 - 1 = 0
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&
p(-1) = (-1)³ - 1 = -1 -1 = (-2)
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p(1) + p(-1) = 0-2= (-2)
Step-by-step explanation:
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