Question

If
P(x)=x^3-1
а ,
then the value of P(1) + P(-1) is
a.0
b.1
c.2
d.-2 ​

Answer 1

-2 is the answer ✔

$P(x)=x^3-1\\P(1)=1^3-1\\=1-1\\\ =0...(1)\\P(-1)=(-1)^3-1\\=-1-1\\ =-2\</p><p>...(2)\\sum of (1) and (2)\\ 0+(-2)\\=0-2\\=-2$

Answer 2

Step-by-step explanation:

ANSWER

P(A)=0.5 and P(AB)=0.8

When A and B are independent events,

P(A∩B)=P(A)×P(B)

⇒P(A)+P(B)−P(A∪B)=0.5×q

⇒0.5+q−0.8=0.5q

⇒0.5q=0.3

⇒q=0.6

When A and B are mutually exclusive events

P(A∩B)=0

P(A)+P(B)=P(A∪B)

0.5+p=0.8

⇒p=0.3

Hence the ratio of q and p is 2

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