Question

if p(x)=x^(3) - 2x^(2) + 5x - 3 then find p (-1)

Answer 1

Answer:

p(x) = x³ - 2x² + 5x - 3

p(-1) = (-1)³ - 2(-1)² + 5(-1) - 3

p(-1) = - 1 - 2 - 5 - 3 = - 11

$\therefore$ Hence, p(-1) = - 11

Answer 2

$\begin{gathered}\begin{gathered}{\huge{\fbox{\fbox{\textbf{\textsf{{\color{orange}{An}}{\orange{sw}}{\orange{er}}}}}}}} \\ \end{gathered}\end{gathered}$

$p(x) = {x}^{3} - 2 {x}^{2} + 5x - 3 \\ \\ when \: \: p( - 1)$

➙ Put x = -1

$( - 1) {}^{3} - 2( - 1) { }^{2} + 5( - 1) - 3 \\ \\ - 1 - 2 - 5 - 3 \\ \\ - 3 - 8 \\ \\ - 11$