Question

if p(x)=x^3-2x^2+x+2 find value of p(-1),p(1),p(0)

Answer 1

Answer:

p(-1)= (-1)^3-2(-1)^2+(-1)+2

= -1-2-1+2

= -2

p(1)= (1)^3-2(1)^2+(1)+2

= 1-2+1+2

= 2

p(0)=(0)^3-2(0)^2+(0)+2

= 0-0+0+2

= 2

Step-by-step explanation:

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