if p(x)=x^3+2x^2+x find p(0) p(2)
Answers
Answered by
0
Answer:
Step-by-step explanation:
p[0]=0^3+2*0^2+0
=0+0+0
=0
p[2]=2^3+2*2^2+2
=8+8+2
=18
Answered by
1
Answer:
Step-by-step explanation:
Given: p(x)=x³+2x²+x
To Find: p(0) and p(2)
Solution:
Case 1:
p(0)=0³+2(0)²+0
=0
Case 2:
p(2)=(2)³+2(2)²+2
=8+8+2
=8+10
=18
hope it helps!
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