Math, asked by anniesabrina11, 10 months ago

if p(x)=x^3+2x^2+x find p(0) p(2)​

Answers

Answered by slikhith21
0

Answer:

Step-by-step explanation:

p[0]=0^3+2*0^2+0

       =0+0+0

         =0

p[2]=2^3+2*2^2+2

        =8+8+2

         =18

Answered by snigdhac2005
1

Answer:

Step-by-step explanation:

Given: p(x)=x³+2x²+x

To Find: p(0) and p(2)

Solution:

Case 1:

p(0)=0³+2(0)²+0

     =0

Case 2:

p(2)=(2)³+2(2)²+2

     =8+8+2

     =8+10

     =18

hope it helps!

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