Math, asked by rutujabhusari88, 11 months ago

If p (x)=x^3+3x^2-2x+1 then find the value of p (2)+p (-2)-p (0)

Answers

Answered by chavan1234
0

P(2)=2^3+3×2^2-2×2+4

p(2)=8+12-4+4

p(2)=24-4

p(2)=20

p(-2)=-2^3+3×-2^2-2×-2+4

p(-2)=-8+12+4+4

p(-2)=20-8

p(-2)=12

p(0)=0^3+3×0^2-2×0+4

p(0)=0+0+0+4

p(0)=4


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